Question

No 10 yg bisa bantu tolong

Answer 1

(x-1)² + (y-2)² = 13
x= 3, maka (y-2)² = 13 - (3-1)²
                    y-2   = √9
                         y = 5 atau y = -1

tentukan gradien di titik tsb:
2(x-1) dx + 2(y-2) dy = 0
                        dy/dx = -2(x-1)/2(y-2)

m = (x-1)/(y-2)

pada titik (3,5)
m = 2/3
pers garisnya: y-5 = (2/3)(x-3)
                         3y = 2x + 9........opsi A

pada titik (3,-1)
m = -2/3
pers garisnya: y+1 = (-2/3)(x-3)
                          3y = -2x + 3

Answer 2

Semoga caranya membantu