Question

Nmer 6 ini kak,bntu yah

Answer 1

Kalau gak salah kayak gini yahh
sin β =4/5
tan β = 4/3
sinβ.tanβ-1 / 2tan kuadrat β = 4/5.(4/3-1)/2(4/3)kuadrat = 4/5. 1/3 / 2 (16/9) =4/15 / 32/9 = 4/5 * 9/32 = 36/480  maaf kalau salah yahhh -_-

Answer 2

Diketahui:
cos β = 3/5, makaaaaaaaaaaaa:
sin β = 4/5
tan β = 4/3

nilai dari:
(sin(β) tan(β) - 1) / (2 tan²(β))
= (4/5 4/3 - 1) / (2 (4/3)²)
= (16/15 - 1) / (2 16/9)
= (1/15) / (32/9)
= 1/15 * 9/32
= 9/480
= 3/160

Kalau Membantu, Jadikan sebagai jawaban terbaik yaaa~~