Question

Nilai x yang memenuhi persamaan eksponensial :

adlah ..............

Answer 1

Verified answer

بِسْمِ اللَّهِ الرَّحْمَنِ الرَّحِيمِ

4^(1-x) + 2^(3-x) - 12 = 0 

4^1 . (2^2)^(-x) + 2^3 . 2^(-x) - 12 = 0 
------------------------------------------------- ( x (2^2x) )

4 + 8(2^x) - 12(2^2x) = 0 

misal 2^2x = a^2 
4 + 8a - 12a^2 = 0 
12a^2 - 8a - 4 = 0 
3a^2 - 2a - 1 = 0 
(3a +1)(a-1) = 0 
a = -1/3 atau a = 1 
(*) 2^x = -1/3 
x = ^2log-1/3 ( TM ) 

(*) 2^x = 1 
2^x = 2^0
x = 0  

SEMOGA MEMBANTU... 

Answer 2

Verified answer

EksPonenSiaL

Misal :
2^x = a

4^(1 - x) + 2^(3 - x) - 12 = 0
4/a² + 8/a - 12 = 0
(4 + 8a - 12a²)/a² = 0
12a² - 8a - 4 = 0 ... ( : 4 )
3a² - 2a - 1 = 0
(3a + 1)(a - 1) = 0
a = -1/3 tdk memenuhi
a = 1
2^x = 1 ---> x = 0

Nilai x yg memenuhi :
x = 0