" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
0 < |x-3|
|x-3| > 0
Kasus 1a:
x-3 > 0
x > 3
Kasus 1b:
x-3 < 0
x < 3
Kasus 2:
|x-3| < 3
-3 < x-3 < 3
Jumlahkan semua dengan 3:
-3+3 < x-3+3 < 3+3
0 < x < 6
Ambil irisan keduanya, didapat:
HP={x | 0 < x < 3 atau 3 < x < 6}
⇔0 + 3 < |x-3+3| <3+3
⇔3 < x < 6