Question

Nilai sin <ACB =...

mohonn bantuannya

Answer 1

ACD dan BCD sebangun
DC = √36-16= 2√5
AC/CB= AD/CD
6/CB=4/2√5
CB=3√5

DB =√(3√5)²-(2√5)²=√25=5
AB= AD+DB=4+5=9
sin ∠ABC= SIN 30=1/2=0,5

AC/sin∠ABC=AB/ sin∠ACB
6/0,5=9/sin∠ACB
sin∠ACB= 9*0,5/6 =3/4