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Verified answer
Jawaby maksimum = √(3²+4²)= 5
sin (2x) = 2sinx.cosx
2 sin (2x) = 2. 2sinx.cosx
2sin(2x) = 4sinx.cosx
nilai maksimum dari sin(2x) adalah 1
maka nilai maksimum dari 2sin(2x) = 2.1 =2