Jawab:
max = 4
min = -6
Penjelasan dengan langkah-langkah:
Nilai maksimum dan minimum fungsi trigonometri [tex]\displaystyle f(x)=a\cos x+b\sin x+c[/tex] adalah
[tex]\begin{aligned}y_{\rm{maks}}&\:=\sqrt{a^2+b^2}+c\\y_{\rm{min}}\:&=-\sqrt{a^2+b^2}+c\end{aligned}[/tex]
[tex]\displaystyle f(x)=y=-4\cos x+3\sin x-1[/tex]
[tex]\begin{aligned}y_{\rm{maks}}&\:=\sqrt{(-4)^2+3^2}-1=4\\y_{\rm{min}}\:&=-\sqrt{(-4)^2+3^2}-1=-6\end{aligned}[/tex]
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Jawab:
max = 4
min = -6
Penjelasan dengan langkah-langkah:
Nilai maksimum dan minimum fungsi trigonometri [tex]\displaystyle f(x)=a\cos x+b\sin x+c[/tex] adalah
[tex]\begin{aligned}y_{\rm{maks}}&\:=\sqrt{a^2+b^2}+c\\y_{\rm{min}}\:&=-\sqrt{a^2+b^2}+c\end{aligned}[/tex]
[tex]\displaystyle f(x)=y=-4\cos x+3\sin x-1[/tex]
[tex]\begin{aligned}y_{\rm{maks}}&\:=\sqrt{(-4)^2+3^2}-1=4\\y_{\rm{min}}\:&=-\sqrt{(-4)^2+3^2}-1=-6\end{aligned}[/tex]