Nilai dari
lim ( ³√8+x -2 )
x-> 0 x
adalah...
ket: -2 diluar akar pangkat tiga
lim ( ³√8+x -2 )
x-> 0 x
adalah...
ket: -2 diluar akar pangkat tiga
arif12
![\lim_{x \to \ 0 } \frac{\sqrt[3]{8+x}-2}{x}](https://tex.z-dn.net/?f=+%5Clim_%7Bx+%5Cto+%5C+0+%7D+++%5Cfrac%7B%5Csqrt%5B3%5D%7B8%2Bx%7D-2%7D%7Bx%7D+++ "\lim_{x \to \ 0 } \frac{\sqrt[3]{8+x}-2}{x}")
![\lim_{x\to \ 0 } \frac{ \sqrt[3]{8+x}- \sqrt[3]{8} }{x}. \frac{(\sqrt[3]{(8+x)^2}+\sqrt[3]{8}. \sqrt[3]{8+x} + \sqrt[3]{8^2} ) }{(\sqrt[3]{(8+x)^2}+\sqrt[3]{8}. \sqrt[3]{8+x} + \sqrt[3]{8^2} )}](https://tex.z-dn.net/?f=+%5Clim_%7Bx%5Cto+%5C+0+%7D++%5Cfrac%7B+%5Csqrt%5B3%5D%7B8%2Bx%7D-+%5Csqrt%5B3%5D%7B8%7D+%7D%7Bx%7D.+%5Cfrac%7B%28%5Csqrt%5B3%5D%7B%288%2Bx%29%5E2%7D%2B%5Csqrt%5B3%5D%7B8%7D.+%5Csqrt%5B3%5D%7B8%2Bx%7D+%2B+%5Csqrt%5B3%5D%7B8%5E2%7D+%29+%7D%7B%28%5Csqrt%5B3%5D%7B%288%2Bx%29%5E2%7D%2B%5Csqrt%5B3%5D%7B8%7D.+%5Csqrt%5B3%5D%7B8%2Bx%7D+%2B+%5Csqrt%5B3%5D%7B8%5E2%7D+%29%7D++ "\lim_{x\to \ 0 } \frac{ \sqrt[3]{8+x}- \sqrt[3]{8} }{x}. \frac{(\sqrt[3]{(8+x)^2}+\sqrt[3]{8}. \sqrt[3]{8+x} + \sqrt[3]{8^2} ) }{(\sqrt[3]{(8+x)^2}+\sqrt[3]{8}. \sqrt[3]{8+x} + \sqrt[3]{8^2} )}")
![\lim_{x \to \ 0 } \frac{8+x-8}{ x(\sqrt[3]{(8+x)^2}+ \sqrt[3]{8}. \sqrt[3]{8+x} + \sqrt[3]{8^2} )}](https://tex.z-dn.net/?f=+%5Clim_%7Bx+%5Cto+%5C+0+%7D++%5Cfrac%7B8%2Bx-8%7D%7B+x%28%5Csqrt%5B3%5D%7B%288%2Bx%29%5E2%7D%2B++%5Csqrt%5B3%5D%7B8%7D.+%5Csqrt%5B3%5D%7B8%2Bx%7D+%2B+%5Csqrt%5B3%5D%7B8%5E2%7D+%29%7D++ "\lim_{x \to \ 0 } \frac{8+x-8}{ x(\sqrt[3]{(8+x)^2}+ \sqrt[3]{8}. \sqrt[3]{8+x} + \sqrt[3]{8^2} )}")
![\lim_{x \to \ 0 } \frac{1}{\sqrt[3]{(8+x)^2}+ \sqrt[3]{8}.\sqrt[3]{8+x} + \sqrt[3]{64} }](https://tex.z-dn.net/?f=+%5Clim_%7Bx+%5Cto+%5C+0+%7D++%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B%288%2Bx%29%5E2%7D%2B+%5Csqrt%5B3%5D%7B8%7D.%5Csqrt%5B3%5D%7B8%2Bx%7D+%2B++%5Csqrt%5B3%5D%7B64%7D+%7D "\lim_{x \to \ 0 } \frac{1}{\sqrt[3]{(8+x)^2}+ \sqrt[3]{8}.\sqrt[3]{8+x} + \sqrt[3]{64} }")
![\frac{1}{ 3.\sqrt[3]{64} }](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B+3.%5Csqrt%5B3%5D%7B64%7D+%7D++ "\frac{1}{ 3.\sqrt[3]{64} }")
2 votes
Thanks 1