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Misal U = (x² + x +1)³
du / dx = 2x + 1 (turunan dari U)
dx = du/(2x+1)
4 ×∫(2x+1).U³dx
4 ×∫(2x+1).U³ . du /(2x+1)
4 ×∫U³.du
= 1/4.U⁴
= Batas 0 sampai 1
4 ×[1/4((1)² + (1) + 1)⁴ ] - [ 1/4((0) + (0) +1)]
=4× [ 81/4 - 1/4]
= 80/4 × 4
= 80
Kunci = A
Ok?