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Verified answer
Jawab4 sin 80 sin 140 sin 200 =
= -2 sin 80 {-2 sin 200 sin 140)
= -2 sin 80 (cos 340 + cos 60)
= - 2 sin 80 (cos (360-20) + 1/2)
= - 2 sin 80 (cos 20 + 1/2)
= - 2 sin 80 cos 20 - sin80
= - (sin 100 + sin 60) - sin 80
= - sin 100 - 1/2√3 - sin 80
= - (sin 100 + sin 80) - 1/2 √3
= - (2 cos 90 cos 10) - 1/2√3
= - (2(0)cos 10) - 1/2√3
= 0 - 1/2√3
= -1/2 √3