nie wiem liczę to i mi nie wychodzi, albo może Profesor sie pomylił.
( 1 + 5 i)/ ( 2 - i) = [ (1 + 5 i)*( 2 + i )]/[ ( 2 - i)*(2 + i)] =
= [ 2 + i +10 i + 5 i^2]/[ 4 - i^2 ] = [ - 3 + 11 i] / [ 4 + 1] =
= - 3/5 + (11/5) i
=================
i^2 = - 1
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( 1 + 5 i)/ ( 2 - i) = [ (1 + 5 i)*( 2 + i )]/[ ( 2 - i)*(2 + i)] =
= [ 2 + i +10 i + 5 i^2]/[ 4 - i^2 ] = [ - 3 + 11 i] / [ 4 + 1] =
= - 3/5 + (11/5) i
=================
i^2 = - 1