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2) 3#2 + 4#5 = (3+4)#(2+5) = 7#7 = 14 + 21 = 35.
3) 9 + 24 = 35.
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1) a Δ b = aᵇ - bᵃ
Hallar: 3 Δ 5
SOLUCION:
3 Δ 5 = 3⁵ - 5³
= 243 - 125
= 118 → Respuesta
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2) Dado: a # b = 2a + 3b
Hallar: 3 # 2 + 4 # 5
SOLUCION:
3 # 2 + 4 # 5 = 2(3) + 3(2) + 2(4) + 3(5)
= 6 + 6 + 8 + 15
= 35 → Respuesta
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3) Se define:
■ x = 2x - 1
▲ x = 3x + 4
Calcular: Ε = ■ 5 + ▲6SOLUCION:
Ε = ■ 5 + ▲6
Ε = 2(5) - 1 + 3(6) + 4
Ε = 10 - 1 + 18 + 4
Ε = 31 → Respuesta
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4) Se define: Δabc = b⁴ - 4ac
Calcular: Δ2,3,4 + Δ3,2,1
SOLUCION:
Δ2,3,4 + Δ3,2,1 = [3⁴ - 4(2)(4)] + [2⁴ - 4(3)(1)]
= [81 - 32] + [16 - 12]
= 49 + 4
= 53 → Respuesta
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