Question

NeQuz
Permutasi Kata Dari

Candi
Prambanan

Museum
Dirgantara


Study Tour Bang ​

Answer 1

Jawaban:

[Permutasi]

Penjelasan dengan langkah-langkah:

Candi Prambanan

C = 1

a = 4

n = 3

d = 1

i = 1

P = 1

r = 1

m = 1

b = 1

Total = 14 unsur

P = Total unsur/Unsur sama

= 14! / 4! 3!

= (14x13x12x11x10x9x8x7x6x5x4x3x2x1)

(4x3x2x1)(3x2x1)

= (14x13x12x11x10x9x8x7x6x5)

(3x2x1)

= (14x13x12x11x10x9x8x7x5)

= (605.404.800) susunan kata

Museum Dirgantara

M = 2

u = 2

s = 1

e = 1

D = 1

i = 1

r = 1

g = 1

a = 3

n = 1

t = 1

r = 1

Total unsur = 16

P = Total unsur

Unsur sama

= 16!

(2!)(2|)(3!)

= (16x15x14x13x12x11x10x9x8x7x6x5x4x3x2x1)

(2x1)(2x1)(3x2x1)

= (16x15x14x13x12x11x10x9x8x7x6x5)

= (871.782.912.000) susunan kata

Study Tour Bang

S = 1

t = 2

u = 2

d = 1

y = 1

o = 1

r = 1

B = 1

a = 1

n = 1

g = 1

Total = 13 unsur

P = Total unsur

Unsur sama

= 13!

(2!)(2!)

= (13x12x11x10x9x8x7x6x5x4x3x2x1)

(2x1)(2x1)

= (13x12x11x10x9x8x7x6x5x3x2x1)

= (1.556.755.200) susunan kata

Detail Jawaban

Mapel : Matematika

Kelas : 10 / [X] SMA

Materi : Permutasi

Kode Kategorisasi : -

Kata Kunci : Permutasi

Demikian

Semofa membantu dan bermanfaat!