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Verified answer
JawabT2oT1 = T2 + T1 = (-1, - 3)
x' = x - 1 → x = x' + 1
y' = y - 3 → y = y' + 3
substitusikan ke (y) - 2(x)² + 3(x) - 4 = 0
(y' +3) - 2(x' +1)² + 3(x'+1) - 4 = 0
y + 3 - 2(x²+2x+1) + 3x + 3 - 4 = 0
y + 3 - 2x² - 4x - 2 + 3x + 3 - 4 = 0
y - 2x² - x = 0