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ctgx=-1
tgx=1/ctgx=-1
sin²x=sin²x/1=sin²x/(sin²x+cos²x)=tg²x/(1+tg²x)
sin²x=1/2⇒sinx=√2/2
cos²x=1/2⇒cosx=-√2/2
Patrz kolo trygonometryczne
lub inczej
ctgx=-1⇒x=135
sin135=√2/2
cos135=-√2/2