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C2H5OH - alkohol etylowy
C7 H15 OH alkohol heptanowy
b)
12n + 2n+1 +17 = 46
14n= 28
n=2
C2 H5 OH alkohol etylowy
b)
Mo=16u
Mc=12u
Mh=1u
CnH2n+1OH
12*n+1*(2n+1)+17=46
14n=46-18
14n=28
n=2
C2H5OH ----etanol