Napisz wzór iloczynowy trójmianu:
a) 2x^2 + 2x - 12
I proszę, napiszcie mi jak to zrobić, nawet streszczając :(
y=2x²+2x-12
a=2
b=2
c=-12
Δ=b²-4ac=4+96=100
√Δ=10
x₁=[-b-√Δ]/2a=[-2-10]/4=-3
x₂=[-b+√Δ]/2a=[-2+10]/4=2
postac iloczynowa;
y=a(x-x₁)(x-x₂)
y=2(x+3)(x-2)
2x^2 + 2x - 12
2(x^2+x-6)
ax^2+bx+c=(x-x1)(x-x2)
a=1
b=1
c=-6
delta=b^2-4ac=1-4*1*(-6)=25
V25=5
x1=(-b-Vdelta)/2a=(-1-5)/2=-3
x2=(-b+Vdelta)/2a=(-1+5)/2=2
2(x+3)(x-2)
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y=2x²+2x-12
a=2
b=2
c=-12
Δ=b²-4ac=4+96=100
√Δ=10
x₁=[-b-√Δ]/2a=[-2-10]/4=-3
x₂=[-b+√Δ]/2a=[-2+10]/4=2
postac iloczynowa;
y=a(x-x₁)(x-x₂)
y=2(x+3)(x-2)
2x^2 + 2x - 12
2(x^2+x-6)
ax^2+bx+c=(x-x1)(x-x2)
a=1
b=1
c=-6
delta=b^2-4ac=1-4*1*(-6)=25
V25=5
x1=(-b-Vdelta)/2a=(-1-5)/2=-3
x2=(-b+Vdelta)/2a=(-1+5)/2=2
2(x+3)(x-2)