Napisz równanie rekacji spalania całkowitego metanu (CH₄) i oblicz ile gramów CO₂ zostanie wyemitowanych do atmosfery podczas spalania 10 kg CH₄
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CH₄ + 2O₂ -----> CO₂ + 2H₂O
MCH₄=12g/mol+4*1g/mol=12g/mol+4g/mol=16g/mol
MCO₂=12g/mol+2*16g/mol=12g/mol+32g/mol=44g/mol
10kg=10000g
10000g CH₄ - xg CO₂
16g CH₄ - 44g CO₂
x=(10000g CH₄*44g CO₂)/16gCH₄=27500g CO₂
16u 44u
CH₄ + 2O₂ --> CO₂ + 2H₂O
10kg x
z proporcji wyliczam x
x = 27,5kg = 27 500g
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