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postać kanoniczna;
y=a(x-p)²+q
y=a(x-5)²-6
6=a(2-5)²-6
6=9a-6
9a=6+6
9a=12
a=12/9
a=4/3
..............
y=4/3(x-5)²-6
y=4/3( x²-10x+25)-6
y=4/3x²-40/3x+100/3-18/3
y=4/3x²-40/3 x+82/3 = równanie paraboli