napisz równania reakcji :
a)
CuO Cu(OH)2
butan-1-ol------------->A------------------>B
T T
d)
HCL KOH CuO
CH2=CH-CH3-------------> A------------>B--------------->C
| H2O T
|
| KOH H2O
|-------------------->D-----------> E
alk.(80Stopni) H
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a) CH3-CH2-CH2-CH2OH+CuO-> CH3-Ch2-CH2-CHO + Cu + H2O
CH3-CH2-CH2-CHO+Cu(OH)2-> CH3-CH2-CH2-COOH + Cu20 + 2H20
d)
CH2=CH-CH3+HCl-> CH3-CHCl-CH3
CH3-CHCl-CH3+KOH-> CH3-CHOH-CH3 + KCl
CH3-CHOH-CH3 + CuO -> CH3-C(wiązanie podwójne w dół)O-CH3 + Cu + H2O
CH3-CHCl-CH3+KOH-alk.-> CH2=CH-CH3 +KCl + H2O
CH2=CH-CH3 + H20-> CH3-CHOH-CH3(Nie jestem pewien).
Jeżeli cos niejasne, zapraszam na priv
przeoczyłem to, sry
a)
CH3-CH2-CH2-CH2-OH + CuO ---> CH3-CH2-CH2-CHO + Cu + H2O
CH3-CH2-CH2-CHO +2 Cu(OH)2 ---> CH3-CH2-CH2-COOH + Cu2O + 2H2O
d)
CH2=CH-CH3 + HCl ---> CH3-CH(Cl)-CH3
CH3-CHCl-CH3 + KOH --H2O--> CH3-CH(OH)-CH3 + KCl
CH3-CH(OH)-CH3 + CuO ---> CH3-C(O)-CH3 + Cu + H2O
CH3-CH(Cl)-CH3 + KOH --EtOH--> CH2=CH-CH3 + KCl + H2O
CH2=CH-CH3 + H2O ---> CH3-CH(OH)-CH3