Napisz cząsteczkowe i jonowe równanie reakcji otrzymywania siarczanu IV baru.
Ba(NO3)2 + Na2SO4------> BaSO4↓ + 2NaNO3
Ba [2+] + 2NO3 [-] + 2Na [+] + SO4 [2-] -----> BaSO4↓ + 2Na [+] + 2NO3 [-]
Ba [2+] + SO4 [2-] ------> BaSO4↓
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Ba(NO3)2 + Na2SO4------> BaSO4↓ + 2NaNO3
Ba [2+] + 2NO3 [-] + 2Na [+] + SO4 [2-] -----> BaSO4↓ + 2Na [+] + 2NO3 [-]
Ba [2+] + SO4 [2-] ------> BaSO4↓