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tg²x
Rozwinięcie Taylora
f(x)=tg²(π) +(x-π)/1!*(tg²π) +(x-π)²/2!*(tg²π)²+(x-π)³/3!*(tg²π)³+(x-π)⁴/4!*(tg²π)₄+(x-π)⁵/5!*(tg²π)⁵+(x-π)⁶/6!*(tg²π)⁶
Z faktu, iż tgπ=0 otrzymujemy:
f(x)= 0