Question

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DAJE NAJ

Answer 1

zad. 5

a) 4²·12²·1/4² = (4/1·12·1/4)² = 12² = 12² = 144
b) (-1 1/2)³·(-1 1/3)³·(-2)³ = [(-1 1/2)·(-1 1/3)·(-2)]³ = [(-3/2)·(-4/3)·(-2)]³ = (-2)³ = -8

zad.6

a) (1/7)²·14²-10⁵·(1/5)⁵ = (1/7·14)² - (10·1/5)⁵ = 2² - 2⁵ = 4 - 32 = -28
b) 35² ÷ (-7)² + (-6)³ ÷ (-2)³ = [35 ÷ (-7)]² + [(-6) ÷ (-2)]³ = (-5)² + 3³ = 25 + 27 = 52
c) 4² · 1/4² - 1/5³ · 5³ = (4/1 · 1/4)² - (1/5 · 5/1)³ = 1² - 1³ = 1 - 1 = 0
d) 3/7³ ÷ (-6/7)³ - 15⁴ ÷ (-5)⁴ = [3/7 ÷ (-6/7)]³ - [15 ÷ (-5)]⁴ = [3/7·(-7/6)]³ - (-3)⁴ = (-1/2)³ - 81 = (-1/8) - 81 = -81 1/8

zad. 7

a) 1/42³ ÷ (-1/21)³ - 100³· (-1/10)³ = [1/42 ÷ (-1/21) - 100·(-1/10)]³ = [1/42·(-21/1) - 10]³ = [(-1/2) - 10]³ = (-10 1/2)³ = -10,5³ = -1157,625
b) 1,2³ ÷ 12³ - 0,6⁵ · (-5/3)⁵ = (1,2 ÷ 12)³ - [0,6·(-5/3)]⁵ = 0,1³ - [3/5·(-5/3)]⁵ = 0,001 - 1⁵ = 0,001 - 1 = -0,999
c) -(-27)³·(-1/9)³ - 12³ ÷ (-3)³ = [-(-27)·(-1/9) - 12 ÷ (-3)]³ = [27·(-1/9) - (-4)]³ = [27·(-1/9) +4]³ = [(-3) + 4]³ = 1³ = 1
d) (-8/3)¹⁵·3/8¹⁵ + (-2/3)² · 3/4² = [(-8/3)·3/8)]¹⁵ + [(-2/3)·3/4]² = (-1)¹⁵ + 1/2² = -1 + 1/4 = -3/4

Mam nadzieję że wszystko zrobiłam dobrze...
/ to ułamki :)