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jedna przyprostokątna ma 12 (10+2)
druga 2+ x
przeciwprostokątna 10+x
z tw. pitagorasa
(x+2)² + 12²= (x+10)²
x²+4x+4+144= x²+20x+100 |x²sie skróci
16x=48
x=3
P=1/2* 12*(2+x) = 6* (2+3)= 30
b=x+r=12
OBL S
S=xr+yr+r²
x+r=12
x+2=12
x=10
Z tw Pitagorasa
(x+y)²=(x+r)²+(y+r)²
x²+2xy+y²=x²+2xr+r²+y²+2yr+r²
2xy=2r(x+y+r)
xy=r(x+y+r)
10y=20+2y+4
8y=24
y=3
podstawiam do pole
S=xr+yr+r²=20+6+4=30
ODP s=30
SPR
a=y+r=5
b=x+r=12
S=1/2*5*12=30
pozdrawiam
Hans