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ms CuSO4 * 5H20 = 63,55+32+64+10+80=249,55u
mrozp1=90u
Cu²⁺ więc 150 cz H2O
mrozp2=90+150=240 u
mr=249,55+240=489,55 u
C%=ms*100%/mr=249,55u*100%/489,55u= 50,97 %
Jak co pisz na PW.