Question

Na dziś...

zad,1.(sin alfa + cos alfa)²+sin alfa-cos alfa)²

zad.2. 1+tg² alfa

prosze o wszystkie równiania

Answer 1

chodzi o zapisanie tego w najprostszej postaci?

zadanie 1

 

zadanie 2

 

 

Answer 2

1.

[sin(a) + cos(a)]^2 + [sin(a) - cos(a)]^2 = 

sin^2(a) + 2sin(a)cos( + cos^2(a) + sin^(a) -2sin(a) cos(a) + cos^2(a) =

= sin^(a) + coss^2(a) + sin^2(a) + cos^2(a) = 1+1 = 2 

 

2.

1 + tg^2(a) = 1 + sin^2(a)/cos^2(a) = cos^2(a)/cos^2(a) + sin^2(a) = 

= [cos^2(a) + sin^2(a)]/cos^(a) = 1/cos^2(a)