na 6 g miedzi z glinem uczen podzial kwasem solnym i uzyskal 3,36 dm^3 wodoru w warunkac normalnych oblicz mase miedzi w tym stopie
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Cu + HCl ---X--->
2Al + 6HCl = 2AlCl3 + 3H2
54gAl------------------3*22,4dm3H2
xg----------------------3,36dm3H2
X=2,7gAl i 6-2,7=3,3gCu