Question

N=(8sen 60° x cos 45°)² - (3 tg 30° x csc 45° ) ² - (csc 60 ° - Ctg 30°) ²

alguien sabe cómo se hace?​

Answer 1

Verified answer

Respuesta:

N= -1/3

Explicación paso a paso:

Sen(60°)= √3/2

Cos(45°)= √2/2

Tg(30°)= √3/3

Csc(45°)= √2

Csc(60°)= 2√3/3

Ctg(30°)= √3

Piden:

N=(8sen60°xCos45°)²-(3Tg30°xCsc45°)²-(Csc60°-Ctg30°)²

N=(8√3/2 x √2/2)²-(3√3/3x√2)²-(2√3/3-√3)²

N=(√6)²-(√6)²-(-√3/3)²

N= -1/3