musza wyjsc 2 rozwiazania oba z pierwiastkami
(2x-3)/6x=2/(2x+3)
x≠0 x≠-3/2
mnozymy na krzyz
4x²+6x-6x-9=12x
4x²-12x-9=0
delta=144+144=288
x1=12-12√2/8=12(1-√2)/8=3(1-√2)/2
x2=12+12√2/8=12(1+√2)/8=3(1+√2)/2
założenie;
x≠0
2x+3≠0 , czyli 2x≠3 , czyli x≠1,5
=
2×6x=(2x-3)(2x+3)
12x=4x²-9
Δ=b²-4ac=144+144=288
√Δ=√288=12√2
x₁=[-b-√Δ]/2a=[12-12√2]/8=1,5-1,5√2=1,5(1-√2)
x₂=[-b+√Δ]/2a=[12+12√2]/8=1,5+1,5√2=1,5(1+√2)
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(2x-3)/6x=2/(2x+3)
x≠0 x≠-3/2
mnozymy na krzyz
4x²+6x-6x-9=12x
4x²-12x-9=0
delta=144+144=288
x1=12-12√2/8=12(1-√2)/8=3(1-√2)/2
x2=12+12√2/8=12(1+√2)/8=3(1+√2)/2
założenie;
x≠0
2x+3≠0 , czyli 2x≠3 , czyli x≠1,5
=
2×6x=(2x-3)(2x+3)
12x=4x²-9
4x²-12x-9=0
Δ=b²-4ac=144+144=288
√Δ=√288=12√2
x₁=[-b-√Δ]/2a=[12-12√2]/8=1,5-1,5√2=1,5(1-√2)
x₂=[-b+√Δ]/2a=[12+12√2]/8=1,5+1,5√2=1,5(1+√2)