Question

mtk bantu ya bang , pake jalan.​

Answer 1

Verified answer

Jawaban:

[tex]\sf s = 6 cm [/tex]

[tex]\sf EG = FH = 6\sqrt{2} \: cm[/tex]

[tex]\sf PF = \frac{6\sqrt{2} }{2} = 3\sqrt{2} [/tex]

[tex]\sf FB = 6 [/tex]

[tex] \sf BP = \sqrt{ {PF}^{2} + {FB}^{2} } [/tex]

[tex] \sf = \sqrt{ {(3 \sqrt{2}) }^{2} + {6}^{2} } [/tex]

[tex] \sf = \sqrt{(9.2) + 36} [/tex]

[tex] \sf = \sqrt{18 + 36} [/tex]

[tex] \sf = \sqrt{54} [/tex]

[tex] \sf = \sqrt{ {3}^{2} \times 6} [/tex]

[tex] \sf = 3 \sqrt{6} \: cm[/tex]

Jadi, jarak antara titik B dan titik P adalah [tex]\sf 3\sqrt{6} [/tex]

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