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R=6cm
2r=2
r=1cm
V1=(4/3)πR³
V2=(4/3)πr³
V1/V2 - ilość małych kul
V1/V2=[(4/3)πR³]/[(4/3)πr³]=R³/r³=6³/1³=216/1=216
Otrzymano 216 małych ku