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H: 6.72 g / 1 g/mol = 6.72 mol
O= 53.3 g / 16 g/mol = 3.331 mol
dividir entre el menor de los resultados
C: 3.333 mol / 3.331 mol = 1
H: 6.72 mol / 3.331 mol = 2
O: 3.331 mol / 3.331 mol =1
FE: CH2O
MASA MOLECULAR DE LA FE
C: 1 X 12 = 12 g/mol
H: 2 x 1 = 2 g/mol
O: 1 x 16 = 16 g/mol
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Mm = 30 g/mol
n= 180 g/mol / 30 g/mol = 6
FM = FEn
FM = (CH2O)6 = C6H12O6