Question

Diketahui data energi ikatan:
C – C = 348 kJ/mol O = O = 500 kJ/mol
C – H = 415 kJ/mol C = O = 724 kJ/mol
O – H = 463 kJ/mol

Tentukan ΔH pada reaksi pembakaran 1 mol propana (C3H8)!

Answer 1

CH3 - CH2 - CH3 + 5O=O → 3 O=C=O + 4 H-O-H

ΔH = ∑I reaktan - ∑I produk
     = [8 C-H + 2 C-C + 5 O=O] - [3 (2 C=O) + 4 (2 O-H)]
     = [(8 × 415) + (2 × 348) + (5 × 500)] - [(6 × 724) + (8 × 463)]
     = - 1532 kJ/mol