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∆H = (∆H°f CO2 + 2 (∆H°f H2O) - (∆H°fCH4 + ∆H°f O2)
891 kJ = (-394 + 2 (-286 ) ) - (∆H°f CH4 + 0)
891 kJ = -966 - (∆H°f CH4)
(∆H°f CH4) = -966 - 891
= 1857 kJ/mol