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= √ ( 10^ -14 ÷10^ -5) × ( 1,96 ÷ 98 ) × ( 1000 ÷ 200 ) = 10^ -5
pOH = 5 ⇒ pH = 9
= x
=
=0,1
[OH-] =
=
=
=
pOH = -log [OH-]
= -log [
= 5
pH = 14-5
=9 (a)
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