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H = 1 g/mol
C = 79,49 g / 12 g/mol = 6.624 mol
H = 20.51g / 1 g/mol = 20.51 mol
dividir cada elemento entre el menor de los resultados
C = 6.624 mol / 6.624 mol = 1
H = 20.51 MOL / 6.624 mol = 3
FORMULA EMPIRICA = C₁H₃
CALCULAR MASA MOLECULAR DELA FE
C = 1 x 1g = 1 g/mol
H = 3 x 1 g/mol = 3 g/mol
¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨
Mm = 4 g/mol
n = Mm / Mm Fe
n = 120 g/mol / 4 g/mol = 30
FORMULAMOLECULA = (C₁H₃)n = (C₁H₃)₃₀ = C₃₀H₉₀