Question

Mohon ka dijawab dengan rinci°∆°

Answer 1

Verified answer

G = 10 m/s²
ma = 4 kg
mb = 1 kg
mc = 2 kg
μa = 0,4
μb = 0,4

fa = μa × Na
= 0,4 × ma × g
= 0,4 × 4 × 10 = 16 N

fb = μb × Nb
= 0,4 × mb × g
= 0,4 × 1 × 10 = 4 N

Pada benda A:
£ F = m × a
T - fa = ma × a1
T - 16 = 4 a1
T = 4(a1) + 16

Pada benda B:
£ F = m × a
T - fb = mb × a2
T - 4 = a2
4(a1) + 16 - 4 = a2
4a1 + 12 = a2

Pada benda C:
£ F = m × a
w - 2T = mc × a3
mc × g - 2T = mc × a3
20 - 2T = 2(a3)

karena a3 = ½(a1 + a2)
maka 2a3 = a1 + a2

20 - 2T = a1 + a2
20 - 2T = a1 + (4a1 + 12)
20 - 2T = 5a1 + 12
20 - 2(4(a1) + 16) = 5a1 + 12
-25 = 5a1 + 8a1
13a1 = -24
a1 = -1,85 m/s² (perlambatan)

T = 4(-1,85) + 16
T = 8,6 Newton

Jadi besar tegangan tali = 8,6 N


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