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syarat stasioner, f'(x) = 0
4x³ - 16x = 0
4x (x² - 4) = 0
4x (x + 2) (x - 2) = 0
x = 0 atau x = -2 atau x = 2
nilai stasioner:
f(0) = 0⁴ - 8.0² + 5 = 5
f(-2) = (-2)⁴ - 8. (-2)² + 5 = 16 - 32 + 5 = - 11
f(2) = 2⁴ - 8.(2)² + 5 = 16 - 32 + 5 = -11
nilai ujung interval: [-3,1]
f(-3) = (-3)⁴ - 8.(-3)² + 5 = 81 - 72 + 5 = 14
f(1) = 1⁴ - 8.(1)² + 5 = 1 - 8 + 5 = -2
maka nilai minimumnya adalah -11
semoga membantu ya :)