Question

MOHON DIBANTUUU KAKK BUAT BESOKKKK

Answer 1

berarti ...

π(integral sin² 2x) dx, batas bawah 0, batas atas π/2 =

π (1/2(1-cos 4x)), batas bawah 0, batas atas π/2 =

π(integral 1/2 dx - 1/2 .integral cos (4x)) dx =

misal u = 4x --> du = 4 dx

dx = 1/4 du

jadi volumenya =

π( 1/2x - 1/8 integral cos u du)=

π(1/2x - 1/8 sin u) =

π(1/2x - 1/8 sin(4x)) =

dari x = 0 sampe x = π/2

= π(1/2.π/2 - 1/8.sin (4.π/2)) - (1/2.0 - 1/8.sin (4.0)) =

π(1/4π - 1/8.sin 2π) - (0-1/8.sin 0) =

π(1/4π - 1/8) - (-1/8) =

π(1/4π) =

π²/4