Mohon dibantu,kerjakan tugas pr tgl 04 itu no 1 dan no 2 thanks
romayuli05
1. F=(k .q1.q2)/r^2 a.dik : Fx=F q1x=q q1y= 6q dit : Fy...? antara F dan q berbanding lurus Fx/Fy = q1x/q1y F/Fy = q/6q Fy = 6F
b. dik : r1 =r r2 = 4r F1=F dit : F2 ...?? antara F dan r^2 berbanding terbalik F1/F2 =(r^2)2/(r^2)1 F / F2 = (4r)^2/ r^2 F / F2 = 16 F2 =(1/16)F
2. dik : k = 9 x 10^9 q1 =3 x 10^(-6) q2 =64 x 10^(-4) F = 27 x 10^3 dit r ....?? jawab : F = (k .q1.q2)/r^2 r^2 = (k.q1.q2)/ F r^2= {( 9 x10^9 )(3.!0^(-6))(64.10^(-4))} / (27.10^3) r^2 = 64 .10^9.10^(-6). 10^(-4) .10^(-3) r^2 = 64 . 10^(-4) r = 8 .10^(-2)
a.dik :
Fx=F
q1x=q
q1y= 6q
dit : Fy...?
antara F dan q berbanding lurus
Fx/Fy = q1x/q1y
F/Fy = q/6q
Fy = 6F
b. dik :
r1 =r
r2 = 4r
F1=F
dit : F2 ...??
antara F dan r^2 berbanding terbalik
F1/F2 =(r^2)2/(r^2)1
F / F2 = (4r)^2/ r^2
F / F2 = 16
F2 =(1/16)F
2. dik :
k = 9 x 10^9
q1 =3 x 10^(-6)
q2 =64 x 10^(-4)
F = 27 x 10^3
dit r ....??
jawab :
F = (k .q1.q2)/r^2
r^2 = (k.q1.q2)/ F
r^2= {( 9 x10^9 )(3.!0^(-6))(64.10^(-4))} / (27.10^3)
r^2 = 64 .10^9.10^(-6). 10^(-4) .10^(-3)
r^2 = 64 . 10^(-4)
r = 8 .10^(-2)