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β = 60°
w = 500 N
ditanya : T1 dan T2
w / sin 90° = T1 / sin (90 + β)
500 / 1 = T1 / sin 150°
500 = T1 / 0,5
T1 = 500 . 0,5
T1 = 250 N
w/sin 90° = T2 / sin (90 + α)
500 / 1 = T2 / sin 120°
500 = T2 / (1/2√3)
T2 = 500 . 1/2 √3
= 250√3 N
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