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AO = 1 m
FB = 10 N
BO = 2 m
β = 45°
ditanya : ∑ τ dan arahnya
Σ τ = FA . AO + FB .BO .sin β
= 25 . 1 + 10 . 2 . sin 45°
= 25 + 20 . 1/2√2
= 25 + 10√2 Nm
karena ∑ τ bernilai positif maka torsi bergerak searah dengan jarum jam