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• Momen gaya
Fa = 25 N, ra = 2 m
Fb = 10 N, αb = 45°, rb = 1 m
τo = __?
Momen gaya terhadap O (arah positif, searah putaran jarum jam
τo = τa - τb
τo = Fa ra - Fb sin αb rb
τo = (25)(1) - (10 • ½√2)(2)
τc = 24 - 10√2 = 11 Nm ← jwb
(searah putaran jarum jam)