Question

Mohon bntuannya (1A) . . .

Answer 1

F₁ = 120 N, α₁ = 45º, r₁ = 1 m
F₂ = 100 N, α₂ = 90º, r₂ = 0,5 m
F₃ = 150 N, α₃ = 45º, r₃ = 1 m

Momen gaya terhadap titik O
τ₀ = F₁ sin α₁ r₁ + F₂ sinα₂ r₂ + F₃ sinα₃ r₃
τ₀ = 120 sin 45° × 1 + 100 sin 90° × 0,5 + 150 sin 45° × 1
τ₀ = 120 · ½√2 × 1 + 100 · 1 × 0,5 + 150 · ½√2 × 1
τ₀ = 60√2 + 50 + 75√2
τ₀ = (50 + 135√2) Nm  ← jawaban