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P = 1 atm
T = (20 + 273)° = 293° K
ditanya : ρ.udara
P.udara.V.udara = n.udara . R .T
P.udara.V.udara = (m.udara /M.udara) R. T
1 .V.udara = (m.udara /28,8) 8,31 . 293
V.udara = m.udara . 84,5 ... bagi dgn m.udara
V.udara / m.udara = 84,5
m.udara / V.udara = 1/84,5
ρ.udara = 1 x 10 /845
= 0,012 kg/m³