Question

Mohon bantuanya teman2 sekalian ​

Answer 1

1) NH4OH : NH4Cl = 2 : 6 => 1:3

[OH⁻] = Kb x [Bl]/[g] x v

[OH⁻] = 2 x 10⁻⁵ x 1/3 x 1

[OH⁻] = 2/3 x 10⁻⁵

POH = 5-log 2/3

PH =9 + log 2/3

2) [H⁺] = Ka x [Al]/[g]v

10⁻⁵ = 10⁻⁵ x 10/[g] x 1

[g] = 10 mmol

n = m/Mr ->> m = nMr

m = 10 x 40 = 400 mg = 0,4 gr