Mohon bantuannya,serta cranya gmana? cara cpat juga bgus??
MathSolver74
Saya bantu nmr 2) int (6x + 3) dx/(x² + x - 6) = int 3(2x + 1)dx/(x² + x - 6) misal: u = x² + x - 6 du = 2x + 1 dx maka: int 3(2x + 1) dx/(x² + x - 6) = int 3 du/u = 3 ln u + c = 3 ln (x² + x - 6) + c
2) int (6x + 3) dx/(x² + x - 6)
= int 3(2x + 1)dx/(x² + x - 6)
misal: u = x² + x - 6
du = 2x + 1 dx
maka:
int 3(2x + 1) dx/(x² + x - 6)
= int 3 du/u
= 3 ln u + c
= 3 ln (x² + x - 6) + c
3) int sin x dx = - cos x + c