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r1 = (2t)i + (1 + 3t^2 ) j
=[2 (0) ] i + [1 + 3 (0)^2 ] j
=0
r2 =(2t)i + (1 + 3t^2 ) j
=[2 (2) ] i + [1 + 3 (2)^2 ] j
=4i + (1 + 12) j
=4i + 13j
Δr = 4i + 13j
| Δv | = √Δx^2 + Δy^2
=√4^2 + 13^2
=√16 + 169
=√185
=13,6
arah perpindahan
tan Ф = Δy / Δx = 13 / 4 = 72,89 Dejad
NB: ^ pangkat
Maff kalau salah :)