Mapel : Kimia
Kelas : 11
Materi : Kesetimbangan Ion Dalam Larutan
Kata Kunci : Ion Senama, pH
Penyelesaian
26.
s Mg(OH)2 = 5×10-²
s = M
Mg(OH)2 → Mg²+ + 2OH-
Valensi basa = 2
[OH-] = 2×5×10-²
[OH-] = 10-³
pOH = -log[OH-]
pOH = -log10-³
pOH = 3
pH = pkw - pOH
pH = 14-3
pH = 11
27. misalkan kelarutan Mg(OH)2 dalam NaOH = s
Ksp Mg(OH)2 = 1,8×10-¹¹
NaOH = 0,1M
NaOH → Na+ + OH-
0,1 → 0,1 + 0,1
[OH-] = 0,1M
Mg(OH)2 → Mg²+ + 2OH
ksp = s + 2s
1,8×10-¹¹ = s (0,1)²
1,8×10-¹¹ = s 10-²
s = 1,8×10-¹¹/10-²
s = 1,8×10^-9 mol/L
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Mapel : Kimia
Kelas : 11
Materi : Kesetimbangan Ion Dalam Larutan
Kata Kunci : Ion Senama, pH
Penyelesaian
26.
s Mg(OH)2 = 5×10-²
s = M
Mg(OH)2 → Mg²+ + 2OH-
Valensi basa = 2
[OH-] = 2×5×10-²
[OH-] = 10-³
pOH = -log[OH-]
pOH = -log10-³
pOH = 3
pH = pkw - pOH
pH = 14-3
pH = 11
27. misalkan kelarutan Mg(OH)2 dalam NaOH = s
Ksp Mg(OH)2 = 1,8×10-¹¹
NaOH = 0,1M
NaOH → Na+ + OH-
0,1 → 0,1 + 0,1
[OH-] = 0,1M
Mg(OH)2 → Mg²+ + 2OH
ksp = s + 2s
1,8×10-¹¹ = s (0,1)²
1,8×10-¹¹ = s 10-²
s = 1,8×10-¹¹/10-²
s = 1,8×10^-9 mol/L
Mapel : Kimia
Kelas : 11
Materi : Kesetimbangan Ion Dalam Larutan
Kata Kunci : Ion Senama, pH
Penyelesaian
26.
s Mg(OH)2 = 5×10-²
s = M
Mg(OH)2 → Mg²+ + 2OH-
Valensi basa = 2
[OH-] = 2×5×10-²
[OH-] = 10-³
pOH = -log[OH-]
pOH = -log10-³
pOH = 3
pH = pkw - pOH
pH = 14-3
pH = 11
27. misalkan kelarutan Mg(OH)2 dalam NaOH = s
Ksp Mg(OH)2 = 1,8×10-¹¹
NaOH = 0,1M
NaOH → Na+ + OH-
0,1 → 0,1 + 0,1
[OH-] = 0,1M
Mg(OH)2 → Mg²+ + 2OH
ksp = s + 2s
1,8×10-¹¹ = s (0,1)²
1,8×10-¹¹ = s 10-²
s = 1,8×10-¹¹/10-²
s = 1,8×10^-9 mol/L