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df/da.da/dx = dg/db.db/dx
df/da.(1-(1/2.√x)) = dg/db.(2x-(1/2)(2x)(1/(√(x²-12)))
f'(2)(3/4) = g'(14)((8)-(4/2))
g'(14)/f'(2) = 6/(3/4)
= 8...opsi A